Question

Точка, двигаясь прямоленейно с постоянным ускорением, набрала 26м/с за 10с. Известно, что ускорение = 2м/с. Какова начальная скорость точки? Найдите перемещение точки за 10 сек

Answer 1

Ответ:

Начальная скорость 6 м/с;

Перемещение за 10 с равно 160 м;

Объяснение:

v₁ = 26 м/с

t₁ = 10 c

a = 2 м/с²

--------------------

v₀ - ?

s₁ - ?

---------------------

Cкорость при равноускоренном движении определяется по формуле

v₁ = v₀ + at₁

откуда начальная скорость

v₀ = v₁ - at = 26 - 2 · 10 = 6 (м/с)

Перемещение точки за 10 с

s₁ = v₀t₁ + 0.5 at₁² = 6 · 10 + 0.5 · 2 · 10² = 160 (м)

Answer 2

Question Analysis

The question is asking for the initial velocity of a point and the displacement of the point after 10 seconds. The point is moving in a straight line with a constant acceleration of 2 m/s^2 and has reached a velocity of 26 m/s after 10 seconds.

Answer

To find the initial velocity of the point, we can use the equation of motion:

v = u + at

where: - v is the final velocity (26 m/s), - u is the initial velocity (unknown), - a is the acceleration (2 m/s^2), and - t is the time (10 s).

Rearranging the equation, we get:

u = v - at

Substituting the given values, we have:

u = 26 m/s - 2 m/s^2 * 10 s

Calculating the value, we find:

u = 26 m/s - 20 m/s

u = 6 m/s

Therefore, the initial velocity of the point is 6 m/s.

To find the displacement of the point after 10 seconds, we can use another equation of motion:

s = ut + (1/2)at^2

where: - s is the displacement (unknown), - u is the initial velocity (6 m/s), - a is the acceleration (2 m/s^2), and - t is the time (10 s).

Substituting the given values, we have:

s = 6 m/s * 10 s + (1/2) * 2 m/s^2 * (10 s)^2

Calculating the value, we find:

s = 60 m + 100 m

s = 160 m

Therefore, the displacement of the point after 10 seconds is 160 meters.

Summary

- The initial velocity of the point is 6 m/s. - The displacement of the point after 10 seconds is 160 meters.

Please let me know if there is anything else I can help you with!