Question

Шар вращается вокруг оси, что проходит через центр шара, с угловым ускорением ε = 4рад / с-2. Вращяющий момент М = 0,12 Н · м. Найти момент инерции Шара.

Answer 1

Ответ:

0,03 кг*м²

Объяснение:

ε = 4 рад/с²    M=0.12 Н*м    J=?

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J=M/ε=0.12/4=0.03 кг*м²

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Answer 2

Finding the Moment of Inertia of a Sphere

To find the moment of inertia of a sphere, we need to know the angular acceleration (ε) and the torque (M) acting on the sphere. In this case, the given values are ε = 4 rad/s^2 and M = 0.12 N·m.

The moment of inertia (I) of a sphere rotating about its axis is given by the formula:

I = M / ε Substituting the given values, we can calculate the moment of inertia of the sphere:

I = 0.12 N·m / 4 rad/s^2

Calculating the above expression, we find:

I = 0.03 kg·m^2

Therefore, the moment of inertia of the sphere is 0.03 kg·m^2.

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