Question

В посудені міститься 2 кг води при температурі 20 С.До неї долили 1,5 кг води за температури 60 С.Яка температура суміші.

Answer 1

Ответ: 37,1°С

Объяснение:

Формула расчет смеси воды:

TС = (V1*T1 + V2*T2) / (V1 + V2), где

TС - температура смеси

V1 - объем горячей воды

T1 - температура горячей воды

V2 - объем холодной воды

T2 - температура холодной воды

TC=(2*20+1,5*60)/(2+1,5)=37,1°С

Answer 2

Problem Analysis

We have a container with 2 kg of water at a temperature of 20°C. We then add 1.5 kg of water at a temperature of 60°C to the container. We need to find the final temperature of the mixture.

Solution

To find the final temperature of the mixture, we can use the principle of conservation of energy. The total heat gained by the water in the container should be equal to the total heat lost by the water that was added.

We can use the formula:

m1 * c1 * (Tf - T1) = m2 * c2 * (T2 - Tf)

Where: - m1 is the mass of the first water sample (2 kg) - c1 is the specific heat capacity of water (4.18 J/g°C) - Tf is the final temperature of the mixture (unknown) - T1 is the initial temperature of the first water sample (20°C) - m2 is the mass of the second water sample (1.5 kg) - c2 is the specific heat capacity of water (4.18 J/g°C) - T2 is the initial temperature of the second water sample (60°C)

We can rearrange the formula to solve for Tf:

m1 * c1 * Tf - m1 * c1 * T1 = m2 * c2 * T2 - m2 * c2 * Tf

Tf * (m1 * c1 + m2 * c2) = m1 * c1 * T1 + m2 * c2 * T2

Tf = (m1 * c1 * T1 + m2 * c2 * T2) / (m1 * c1 + m2 * c2)

Now we can substitute the values into the formula and calculate the final temperature.

Calculation

Let's calculate the final temperature of the mixture using the given values:

m1 = 2 kg c1 = 4.18 J/g°C T1 = 20°C m2 = 1.5 kg c2 = 4.18 J/g°C T2 = 60°C

Tf = (2 * 4.18 * 20 + 1.5 * 4.18 * 60) / (2 * 4.18 + 1.5 * 4.18)

Tf = (167.2 + 376.74) / (8.36 + 6.27)

Tf = 543.94 / 14.63

Tf ≈ 37.22°C

Answer

The final temperature of the mixture is approximately 37.22°C.