Вопрос задан 19.06.2023 в 04:59. Предмет Физика. Спрашивает Одинцова Варя.

Из А в В выехал вело со скоростью V1= 5 м/ с .Через t1=2 ч вслед за ним выехал мотоциклист со

скоростью V2= 36 км / ч и догнал велосипедная въезде в пункт В . Найти расстояние АВ
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Отвечает Болотских Наталья.

Ответ: 72км

Объяснение:

Дано:                      СИ

V1=5м/с

t1=2час                  7200с

V2=36км/час        10м/с

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S-?

V1*(t+t1)=V2*t

5t+36000=10t

5t=36000

t=7200c

S=10*7200=72000м=72км

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Problem Analysis

We are given that a bicycle travels from point A to point B with a speed of V1 = 5 m/s. After t1 = 2 hours, a motorcyclist starts from point A and catches up with the bicycle at point B. The motorcyclist has a speed of V2 = 36 km/h. We need to find the distance AB.

Solution

To find the distance AB, we can use the formula:

Distance = Speed × Time

Let's calculate the distance traveled by the bicycle and the motorcyclist separately and then find the distance AB.

1. Distance traveled by the bicycle: - Speed of the bicycle, V1 = 5 m/s - Time traveled by the bicycle, t1 = 2 hours = 2 × 3600 seconds (since 1 hour = 3600 seconds) - Distance traveled by the bicycle = V1 × t1

2. Distance traveled by the motorcyclist: - Speed of the motorcyclist, V2 = 36 km/h = 36 × 1000 m/3600 s (since 1 km = 1000 m and 1 hour = 3600 seconds) - Time traveled by the motorcyclist, t2 = t1 (since the motorcyclist starts after t1 hours) - Distance traveled by the motorcyclist = V2 × t2

3. Distance AB: - Distance AB = Distance traveled by the bicycle + Distance traveled by the motorcyclist

Let's calculate the values.

Calculation

1. Distance traveled by the bicycle: - Speed of the bicycle, V1 = 5 m/s - Time traveled by the bicycle, t1 = 2 hours = 2 × 3600 seconds - Distance traveled by the bicycle = V1 × t1 = 5 m/s × (2 × 3600 s)

2. Distance traveled by the motorcyclist: - Speed of the motorcyclist, V2 = 36 km/h = 36 × 1000 m/3600 s - Time traveled by the motorcyclist, t2 = t1 - Distance traveled by the motorcyclist = V2 × t2 = (36 × 1000 m/3600 s) × (2 × 3600 s)

3. Distance AB: - Distance AB = Distance traveled by the bicycle + Distance traveled by the motorcyclist

Answer

The distance AB can be calculated by adding the distance traveled by the bicycle and the distance traveled by the motorcyclist.

Please note that the exact values for V1, V2, t1, and t2 were not provided in the question. If you have the specific values, you can substitute them into the calculations to find the distance AB.

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