Question

Помогитеее !! Срочно ! Шарик массой 200 г, ударился об пол со скоростью 5 м/с и подпрыгнул на высоту 46 см. Найдите изменение импульса шарика во время удара.​

Answer 1

Дано:
m=0,2кг
V=5м/с
h=0,46см

dP=?

Решение:

dP=P-P0=m*V-m*V0
dP=m*V-m*(-V0)=m*V+mV0=m*(V+V0)
(m*V0^2)/2=m*g*h
m*V0^2=2m*g*h
V0^2=2*g*h
V0= √(2*g*h)

dP=m*(V+ √(2*h*g))
dP=0,2*(5+(√2*10*0,46))
dP=1,6кг*м/с

Ответ: dP=1,6кг*м/с.

Answer 2

Calculation of Change in Momentum

To find the change in momentum of the ball during the impact, we can use the formula:

Change in momentum = Final momentum - Initial momentum

The momentum of an object is given by the product of its mass and velocity:

Momentum = mass * velocity

Given: - Mass of the ball (m) = 200 g = 0.2 kg - Initial velocity (u) = 5 m/s - Final velocity (v) = 0 m/s (since the ball comes to rest during the impact)

Let's calculate the initial momentum and final momentum of the ball.

Initial momentum = mass * initial velocity Final momentum = mass * final velocity

Substituting the given values:

Initial momentum = 0.2 kg * 5 m/s Final momentum = 0.2 kg * 0 m/s

Now we can calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum

Please note that the final momentum is zero since the ball comes to rest during the impact.

Let's calculate the change in momentum.