Question

Камень бросили вертикально с высоты 35 м, придав ему скорость 30 м/с в направлении вниз. Чему равна скорость камня в момент падения на землю?

Answer 1

Ответ:

$v =$ 40 м/с

Объяснение:

Дано:

$h = 35$ м

$v_{0} = 30$ м/с

$g =$ 10 м/с²

Найти:

$v - ?$

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Решение:

$v = \sqrt{v_{0}^{2} + 2gh}$

$v =$ √(900 м²/с² + 2 * 10 м/с² * 35) = 40 м/с

Ответ: $v =$ 40 м/с.

Answer 2

Calculation of the stone's velocity at the moment of impact

To determine the velocity of the stone at the moment it hits the ground, we can use the principles of motion and conservation of energy.

Given: - Initial height (h) = 35 m - Initial velocity (v) = 30 m/s (directed downwards)

We can use the equation for the final velocity (vf) of an object in free fall:

vf^2 = vi^2 + 2gh

Where: - vf is the final velocity - vi is the initial velocity - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the height

Plugging in the values, we get:

vf^2 = (30 m/s)^2 + 2 * 9.8 m/s^2 * 35 m

Simplifying the equation:

vf^2 = 900 m^2/s^2 + 686 m^2/s^2

vf^2 = 1586 m^2/s^2

Taking the square root of both sides:

vf ≈ 39.8 m/s

Therefore, the velocity of the stone at the moment it hits the ground is approximately 39.8 m/s.