Question

Огромное спосибо тем кто решит эту задачу мое безграничное спосибо Тело свободно падает в течение 30 секунд. Определите высоту, с которой падает тело и скорость падения.

Answer 1

h- высота, t - время падения, д ускорение свободного падения - скорость падения

h=gt^2/2 = 10*900/2=45000 метров

v=gt=10*30=300 м/с

Answer 2

Дано:t=30с решение:v=v0+gt=10•30=300м/с

найти:h-? составим уравнение движения:
h=h0+v0t+gt(во 2 степени):2(записать дробью)=10•30(во 2 степ)
v-? :2(тоже записать дробью)= 4 500м
ответ:h=4 500м
v=300м/с

Answer 3

I can help you with your question.

Your question is: Answer in detail. Huge thanks to those who solve this problem, my boundless thanks. The body falls freely for 30 seconds. Determine the height from which the body falls and the speed of the fall.

To solve this problem, we need to use the formula for the distance traveled by a body in free fall:

$$s = v_0t + \frac{1}{2}gt^2$$

where $s$ is the distance, $v_0$ is the initial velocity, $t$ is the time, and $g$ is the acceleration due to gravity.

We also need to use the formula for the final velocity of a body in free fall:

$$v = v_0 + gt$$

where $v$ is the final velocity.

Assuming that the body starts from rest, we have $v_0 = 0$. Also, assuming that the gravity is constant and equal to $9.8 m/s^2$, we have $g = 9.8$.

Plugging these values into the formulas, we get:

$$s = 0 + \frac{1}{2}(9.8)t^2 = 4.9t^2$$

$$v = 0 + (9.8)t = 9.8t$$

Substituting $t = 30$, we get:

$$s = 4.9(30)^2 = 4410 m$$

$$v = 9.8(30) = 294 m/s$$

Therefore, the height from which the body falls is $4410 m$, and the speed of the fall is $294 m/s$.

I hope this helps. Have a nice day!