Question

Одноатомний ідеальний газ під час ізобарного нагрівання виконує роботу 8 кДж. Обчислити зміну внутрішньої енергії та кількість теплоти, що передали газу. Відповідь: ДU = 12-10° Дж, Q= 2-10° Дж. Як розв’язати задачу. Допоможіть будь ласка)

Answer 1

Ответ:

Объяснение:

A=8*10³ Дж     ΔU=?    Q=?

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i=3

p=const

ΔU=(i/2)*p*ΔV=(3/2)*A=3*8*10³/2=12*10³ Дж

Q=ΔU+A=(12+8)*10³=20*10³ Дж

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Answer 2

To solve this problem, we need to use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat (Q) added to the system minus the work (W) done by the system:

ΔU = Q - W

In this case, the gas is undergoing isobaric heating, which means the pressure remains constant. The work done by the gas can be calculated using the formula:

W = PΔV

where P is the constant pressure and ΔV is the change in volume.

Since the gas is ideal, we can use the ideal gas law to relate the change in volume to the change in temperature:

ΔV = VΔT

where V is the initial volume of the gas and ΔT is the change in temperature.

Now, let's calculate the change in internal energy (ΔU) and the heat transferred to the gas (Q) using the given information:

Given: Work done by the gas (W) = 8 kJ

To calculate ΔU and Q, we need to know the values of pressure (P), initial volume (V), and the change in temperature (ΔT). Unfortunately, these values are not provided in the question. Can you please provide the values of pressure, initial volume, and the change in temperature?