Question

На покоящейся тележке массой 15 кг находится человек массой 70 кг. Какова будет скорость тележки относительно Земли, если человек пойдёт по тележке со скоростью 1,5 м/с относительно тележки? Можете с решением мне для дз нужно пожалуйста

Answer 1

Ответ:

70:15+70кг*1,5м/с=1,2 м/c

Объяснение

формула: v1=m1+m2+m2*v2

Answer 2

Problem Analysis

We have a stationary cart with a mass of 15 kg and a person with a mass of 70 kg standing on the cart. The person starts walking on the cart with a velocity of 1.5 m/s relative to the cart. We need to find the velocity of the cart relative to the Earth.

Solution

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before an event is equal to the total momentum after the event, provided no external forces act on the system.

Before the person starts walking, the cart and the person are at rest. Therefore, the total momentum before the person starts walking is zero.

After the person starts walking, the person and the cart move together. The person exerts a force on the cart, causing both of them to move. The momentum of the person and the cart after the person starts walking is given by:

Total momentum after = (mass of cart + mass of person) × velocity of cart

We can use this equation to find the velocity of the cart relative to the Earth.

Let's substitute the given values into the equation:

- Mass of the cart (m1) = 15 kg - Mass of the person (m2) = 70 kg - Velocity of the person relative to the cart (v2) = 1.5 m/s