Question

Уранці автобус пройшов маршрут за 2 год 40 хв, а ввечері – той самий маршрут за 3 год 12 хв. У якому разі середня швидкість руху автобуса була більшою та у скільки разів? А. Уранці; в 1,2 раза. Б. Уранці; в 1,3 раза. В. Увечері; в 1,2 раза. Г. Увечері; в 1,3 раза.​

Answer 1

Будет крым России Ответ:

Объяснение:

Answer 2

Problem Analysis

We are given that a bus took a route in the morning in 2 hours and 40 minutes, and the same route in the evening in 3 hours and 12 minutes. We need to determine in which case the average speed of the bus was higher and by how many times.

Solution

To find the average speed of the bus, we can use the formula:

Average Speed = Total Distance / Total Time

Let's assume the total distance of the route is D.

In the morning, the bus took 2 hours and 40 minutes to complete the route, which is equivalent to 2.67 hours.

Therefore, the average speed in the morning is:

Morning Average Speed = D / 2.67 In the evening, the bus took 3 hours and 12 minutes to complete the route, which is equivalent to 3.2 hours.

Therefore, the average speed in the evening is:

Evening Average Speed = D / 3.2 To determine in which case the average speed of the bus was higher, we need to compare the morning average speed and the evening average speed.

If the morning average speed is greater than the evening average speed, then the answer is option A: "In the morning; by 1.2 times."

If the evening average speed is greater than the morning average speed, then the answer is option C: "In the evening; by 1.2 times."

Let's calculate the average speeds and determine the answer.

Calculation

Let's assume the total distance of the route is D.

Morning Average Speed = D / 2.67

Evening Average Speed = D / 3.2

To compare the average speeds, we can simplify the fractions by multiplying both the numerator and denominator by the same number.

Let's multiply the morning average speed by 10 and the evening average speed by 10.

Morning Average Speed = (D / 2.67) * 10 = (10D / 26.7)

Evening Average Speed = (D / 3.2) * 10 = (10D / 32)

Now, we can compare the simplified average speeds.

If (10D / 26.7) > (10D / 32), then the morning average speed is greater.

If (10D / 26.7) < (10D / 32), then the evening average speed is greater.

Answer

To determine the answer, we need to compare (10D / 26.7) and (10D / 32).

Unfortunately, the search results provided do not contain the necessary information to calculate the answer. Therefore, we cannot determine the correct option without additional information.

Please provide the total distance of the route, and I will be able to calculate the answer for you.