Question

ПОМОГИТЕ СРОЧНО!!! Если при работе теплового двигателя рабочее тело за один цикл получило от нагревателя количество теплоты 40 Дж, а холодильнику передало 30 Дж, то КПД равен ... %.

Answer 1

Ответ:

25%

Объяснение:

(Qн-Qх):Qн•100%=25%

(40-30):40•100%

Answer 2

Calculation of Efficiency of a Heat Engine

To calculate the efficiency of a heat engine, we need to know the amount of heat absorbed by the working substance (Qh) and the amount of heat rejected to the cold reservoir (Qc). The efficiency (η) is given by the formula:

η = (Qh - Qc) / Qh * 100%

In this case, the working substance of the heat engine received 40 J of heat (Qh) from the heater and transferred 30 J of heat (Qc) to the refrigerator. We can substitute these values into the formula to calculate the efficiency:

η = (40 J - 30 J) / 40 J * 100%

Simplifying the equation:

η = 10 J / 40 J * 100%

Calculating the value:

η = 0.25 * 100% = 25%

Therefore, the efficiency of the heat engine in this scenario is 25%.

Please note that the sources provided do not contain specific information related to the calculation of the efficiency of a heat engine. The calculation is based on the general principles of thermodynamics.