Question

Период колебаний материальной точки равен 16 с. Считая движение материальной точки во время колебания равнопеременным (равноускоренным или равнозамедленным), определи время, за которое точка пройдёт путь, равный 1/3 амплитуды, если в начальный момент времени точка проходила положение равновесия.

Answer 1

Ответ: 1,63с

Объяснение:

Дано:

T=16c

S=A/3

xo=0

=======

t1-?

Время прохождения маятника от положения равновесия хо равно:

t=T/4=16/4=4c

A=at²/2

a=2A/t²=2A/4²=А/8

А/3=а*t1²/2=A*t1²/8

1/3=t1²/8

t1=√8/3=√2,67=1,63с

Answer 2

Решение на фото/////

Answer 3

Calculation of Time for a Particle to Travel 1/3 of the Amplitude

To calculate the time it takes for a particle to travel a distance equal to 1/3 of the amplitude during its oscillation, we can use the formula for the period of oscillation.

The period of oscillation, denoted as T, is the time it takes for a particle to complete one full cycle of its motion. In this case, the period is given as 16 seconds.

The amplitude, denoted as A, is the maximum displacement of the particle from its equilibrium position. Since the particle starts from the equilibrium position, the amplitude is equal to the initial displacement.

To find the time it takes for the particle to travel a distance equal to 1/3 of the amplitude, we can use the equation:

Time = (1/3) * (T/4)

Here, T/4 represents one-quarter of the period, which is the time it takes for the particle to travel from the equilibrium position to the maximum displacement (amplitude).

Let's substitute the given values into the equation:

Time = (1/3) * (16/4) = 4/3 seconds

Therefore, it will take the particle 4/3 seconds to travel a distance equal to 1/3 of the amplitude.

Please note that the above calculation assumes that the motion of the particle is simple harmonic motion and that the particle starts from the equilibrium position.