Question

Q=2700 кг/м³a=20b=15h=5cмm=?​

Answer 1

Дано:

плотность ρ(q)=2700 кг/м³=2,7 г/см³

Размеры бруска из алюминия (смотрю по плотности)

а=20 см=0,2 м

b=15 см=0,15 м

h=5 см=0,005 м

m - ?

m=ρ*V

m=ρ*(a*b*h)

m=2,7*20*15*5=2,7*100*15=270*15=4050 г≈4 кг  -  это ответ.

Не всегда удобно в СИ. Здесь маленький брусок.

Answer 2

To find the value of "c" in centimeters (cm), we need to use the formula for volume:

V = Q / (a * b * h)

Where: V is the volume, Q is the mass, a is the length, b is the width, h is the height.

Given: Q = 2700 kg/m³ (density) a = 20 (length) b = 15 (width) h = 5 cm (height)

To find the volume in cubic centimeters (cm³), we first need to convert the height from cm to meters (m) since the density is given in kg/m³:

h = 5 cm = 5/100 m = 0.05 m

Now we can substitute the values into the formula:

V = Q / (a * b * h) V = 2700 kg/m³ / (20 * 15 * 0.05 m) V = 2700 / (300 * 0.05) m³ V = 2700 / 15 m³ V = 180 m³

Since we need to find the value of "c" in centimeters (cm), we can use the formula for volume:

V = a * b * c

Rearranging the formula, we have:

c = V / (a * b) c = 180 m³ / (20 * 15) c = 180 m³ / 300 c = 0.6 m

Finally, we convert the value of "c" from meters (m) to centimeters (cm):

c = 0.6 m = 0.6 * 100 cm c = 60 cm

Therefore, the value of "c" is 60 cm.