Question

Газ с плотностью 2кг/м^3 занимает объём 0,7 м^3.Какова молярная масса этого газа, если в нём содержится 3*10^24 молекул?​

Answer 1

Ответ:0,28 кг/моль

Объяснение:

Answer 2

Calculation of Molar Mass of the Gas

To calculate the molar mass of the gas, we need to know the number of moles of the gas and the mass of the gas. We can use the ideal gas law equation to find the number of moles of the gas:

PV = nRT

Where: - P is the pressure of the gas (not given) - V is the volume of the gas (given as 0.7 m^3) - n is the number of moles of the gas (to be calculated) - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (not given)

Since the temperature is not given, we cannot directly calculate the number of moles of the gas using the ideal gas law. However, we are given the number of molecules of the gas, which can be used to calculate the number of moles.

The relationship between the number of moles and the number of molecules is given by Avogadro's number:

1 mole = 6.022 x 10^23 molecules

Given that there are 3 x 10^24 molecules of the gas, we can calculate the number of moles:

n = (3 x 10^24 molecules) / (6.022 x 10^23 molecules/mol)

Let's calculate the number of moles:

n = (3 x 10^24) / (6.022 x 10^23) = 4.977 moles (approximately)

Now that we have the number of moles, we can calculate the molar mass of the gas using the formula:

Molar mass = mass / number of moles

However, we don't have the mass of the gas. To calculate the mass, we can use the density of the gas.

The density of a substance is defined as the mass per unit volume:

Density = mass / volume

Rearranging the equation, we can solve for mass:

Mass = density x volume

Given that the density of the gas is 2 kg/m^3 and the volume is 0.7 m^3, we can calculate the mass:

Mass = 2 kg/m^3 x 0.7 m^3 = 1.4 kg

Now we can calculate the molar mass:

Molar mass = mass / number of moles

Molar mass = 1.4 kg / 4.977 moles = 0.280 kg/mol (approximately)

Therefore, the molar mass of the gas is approximately 0.280 kg/mol.