Question

Пружина растягивается на 7 см под воздействием силы 21Н. Определите коэффициент жесткости пружины.​

Answer 1

Ответ:

300

Объяснение:

Коефициент жесткости=F/L=21 Н/0,07 м=300

Answer 2

Calculation of the Spring Constant

To determine the spring constant of a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:

F = k * x

Where: - F is the force applied to the spring, - k is the spring constant, - x is the displacement of the spring from its equilibrium position.

In this case, we are given that the spring is stretched by 7 cm (or 0.07 m) under the influence of a force of 21 N. We can use this information to calculate the spring constant.

F = k * x 21 N = k * 0.07 m

To find the value of k, we can rearrange the equation:

k = F / x k = 21 N / 0.07 m

Calculating this expression gives us the value of the spring constant:

k ≈ 300 N/m.

Therefore, the spring constant of the given spring is approximately 300 N/m.