Question

Помогите пожалуйста 1) x = 0,1 • cos Пt 2) x = 0,04 • sin 80 Пt 3) x = 0,02 • cos 200 Пt 4) x = 0,1 • cos 0,2 Пt a) 0,1 кГц b) 86 Гц c) 0,1 Гц d) 40 Гц e) 0,5 Нужно ещё решение как вы сделали

Answer 1

Відповідь:

1)x = 0,1 • cos Пt

x=Acos(wt+ф)=>

w=П

w=(2П)/T=> T=(2П)/w=(2П)/П=2

v=1/T=1/2=0.5 Гц-e)

2)x = 0,04 • sin 80 Пt

x=Asin(wt+ф)=>

w=80П

w=(2П)/T=> T=(2П)/w=(2П)/80П=2/80

v=1/T=80/2=40 Гц-d)

3)x = 0,02 • cos 200 Пt

x=Acos(wt+ф)=>

w=200П

T=(2П)/w=(2П)/200П=1/100

v=1/T=100=a) 0,1 кГц

4)x=Acos(wt+ф)=>

w=0.2П

T=(2П)/w=(2П)/0.2П=10

v=1/T=1/10=0.1 c) 0,1 Гц

Пояснення:

Answer 2

Solution for the Given Equations

The given equations are in the form of x = A • sin(Bt) or x = A • cos(Bt), where A and B are constants. Let's analyze each equation:

1. Equation 1: x = 0.1 • cos(Пt) 2. Equation 2: x = 0.04 • sin(80Пt) 3. Equation 3: x = 0.02 • cos(200Пt) 4. Equation 4: x = 0.1 • cos(0.2Пt)

Frequency Analysis

The frequency of a sinusoidal function in the form A • sin(Bt) or A • cos(Bt) is given by B/2π. Let's calculate the frequencies for each equation:

1. Equation 1: Frequency = B/2π = П/2π ≈ 0.159 Hz 2. Equation 2: Frequency = B/2π = 80П/2π ≈ 40 Hz 3. Equation 3: Frequency = B/2π = 200П/2π ≈ 100 Hz 4. Equation 4: Frequency = B/2π = 0.2П/2π ≈ 0.032 Hz

Answer to the Given Question

The frequencies corresponding to the given equations are: a) 0.1 kHz b) 86 Hz c) 0.1 Hz d) 40 Hz e) 0.5 Hz

The frequencies were calculated using the formula B/2π for each equation, where B is the coefficient of t in the cosine or sine function.

I hope this helps! If you have further questions or need additional assistance, feel free to ask.