Question

Тепловой двигатель совершил полезную работу 2,3*10^4 кДж и израсходовал при этом 2 кг бензина. Найти КПД теплового двигателя.

Answer 1

Ответ:

Объяснение:

Aп = 2,3·10⁴ кДж = 2,3·10⁷ Дж

m = 2 кг

q = 4,6·10⁷ Дж/кг

η - ?

============

при полном сгорании бензина выделилось энергии Q₁ = q·m = 4,6·10⁷·2 = 9,2·10⁷ Дж

КПД теплового двигателя η = Ап / Q₁ · 100% = 2,3·10⁷ / (9,2·10⁷) · 100% = 25%

Answer 2

Calculation of Thermal Efficiency

To find the thermal efficiency of a heat engine, we need to know the useful work output and the energy input. In this case, the useful work output is given as 2.3 * 10^4 kJ, and the energy input is the amount of gasoline consumed, which is 2 kg.

The thermal efficiency (η) of a heat engine is defined as the ratio of the useful work output (W) to the energy input (Q):

η = W / Q

Substituting the given values:

η = 2.3 * 10^4 kJ / 2 kg

To calculate the thermal efficiency, we need to convert the energy input from kilograms of gasoline to kilojoules. For this, we need to know the energy content of gasoline.

Unfortunately, the search results provided do not contain the specific information needed to calculate the thermal efficiency in this case. The search snippets do not provide the necessary context or formulas to determine the energy content of gasoline. Therefore, I am unable to provide a precise answer to your question.

If you have any other questions or need further assistance, feel free to ask!