Question

Определить удельное сопротивление поперечного сечения провода сечением 0,5 мм и длиной 4 м. При напряжении 9,6 В по проводу протекает ток силой 2 А.​ ​

Answer 1

Ответ:

0.6 Ом*мм2/м

Объяснение:

R=ro*L/S

I=U/R=US/(ro*L)

ro=US/(L*I)=(9.6*0.5)/(4*2)=0.6 Ом*мм2/м

Answer 2

R=U/I=9,6/2=4,8 Ом R=Рl/S Р=RS/l=4,8х0,5/4=0,6 Омхмм^2/м

Answer 3

Calculating the Specific Resistance of the Wire

To calculate the specific resistance of the wire, we can use the formula:

Specific Resistance (ρ) = Resistance (R) / (Cross-sectional Area (A) * Length (L))

Given: - Cross-sectional area (A) = 0.5 mm² - Length (L) = 4 m - Voltage (V) = 9.6 V - Current (I) = 2 A

First, let's calculate the resistance (R) of the wire using Ohm's law: Resistance (R) = Voltage (V) / Current (I)

Resistance (R) = 9.6 V / 2 A = 4.8 Ω

Now, we can calculate the specific resistance (ρ): Specific Resistance (ρ) = 4.8 Ω / (0.5 mm² * 4 m)

Specific Resistance (ρ) = 4.8 Ω / (0.002 m²) Specific Resistance (ρ) = 2400 Ω/m

So, the specific resistance of the wire is 2400 Ω/m.