Question

500 г жидкости налили в сосуд, площадь дна которого 25см². Определите давление жидкости на дно сосуда.​

Answer 1

25см²=(2,5×10⁻²м)²=0,0025 м²

p=F/S=mg/S=0.5 кг×10м/с²÷0,0025 м²=2000 Па

ответ:2кПа

Answer 2

Calculating Pressure of Liquid on the Bottom of a Vessel

To calculate the pressure of the liquid on the bottom of the vessel, we can use the formula:

Pressure (P) = Density (ρ) × Acceleration due to gravity (g) × Height (h)

Where: - Density (ρ) is the density of the liquid - Acceleration due to gravity (g) is the acceleration experienced by an object due to the gravitational force - Height (h) is the height of the liquid column above the bottom of the vessel

Given that 500 g of liquid is poured into a vessel with a bottom area of 25 cm², we can calculate the pressure using the formula.

Calculation

First, we need to convert the mass of the liquid from grams to kilograms: - 500 g = 0.5 kg

The height of the liquid column can be calculated using the formula: Height (h) = Volume / Area

The volume of the liquid can be calculated using the formula: Volume = Mass / Density

Given that the density of water is approximately 1000 kg/m³, we can use this value for the density of the liquid.

Let's calculate the height of the liquid column and then use it to find the pressure on the bottom of the vessel.

Height Calculation

Using the given mass of the liquid (0.5 kg) and the density of water (1000 kg/m³), we can calculate the volume of the liquid: Volume = Mass / Density Volume = 0.5 kg / 1000 kg/m³ Volume = 0.0005 m³

Now, we can calculate the height of the liquid column: Height (h) = Volume / Area Height (h) = 0.0005 m³ / 0.0025 m² Height (h) = 0.2 m

Pressure Calculation

Now that we have the height of the liquid column, we can calculate the pressure on the bottom of the vessel using the formula: Pressure (P) = Density (ρ) × Acceleration due to gravity (g) × Height (h)

Given that the acceleration due to gravity is approximately 9.81 m/s², we can use this value for the calculation.

Pressure (P) = 1000 kg/m³ × 9.81 m/s² × 0.2 m Pressure (P) = 1962 Pa

So, the pressure of the liquid on the bottom of the vessel is approximately 1962 pascals.