Question

Два проводника соединены параллельно. Сила тока в первом проводнике 0,5 А, а на всем участке цепи – 0,9 А. Сопротивление участка 30 Ом. Определите силу тока во втором проводнике, напряжение на каждом проводнике и на участке цепи, а также сопротивление каждого проводника. Пожалуйста с Дано и Решением СРОЧНО

Answer 1

Ответ:

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Answer 2

Given Information

Two conductors are connected in parallel. The current in the first conductor is 0.5 A, and the total current in the circuit is 0.9 A. The resistance of the circuit segment is 30 Ohms.

Solution

To solve for the current in the second conductor, the voltage on each conductor and the circuit segment, as well as the resistance of each conductor, we can use the following steps:

1. Calculate the Current in the Second Conductor: - The total current in the circuit is the sum of the currents in the two conductors: - \( I_{\text{total}} = I_1 + I_2 \) - We are given \( I_{\text{total}} = 0.9 \, \text{A} \) and \( I_1 = 0.5 \, \text{A} \). We can solve for \( I_2 \).

2. Determine the Voltage on Each Conductor and the Circuit Segment: - The voltage on each conductor can be found using Ohm's law: \( V = I \times R \). - The voltage on the circuit segment can be found using the total current and the resistance of the segment: \( V_{\text{segment}} = I_{\text{total}} \times R_{\text{segment}} \).

3. Calculate the Resistance of Each Conductor: - The resistance of each conductor can be found using Ohm's law: \( R = \frac{V}{I} \).

Results

Using the given information and the above steps, we can calculate the following:

1. Current in the Second Conductor: - \( I_2 = I_{\text{total}} - I_1 \) - \( I_2 = 0.9 \, \text{A} - 0.5 \, \text{A} \) - \( I_2 = 0.4 \, \text{A} \).

2. Voltage on Each Conductor: - \( V_1 = I_1 \times R \) - \( V_1 = 0.5 \, \text{A} \times 30 \, \Omega \) - \( V_1 = 15 \, \text{V} \). - \( V_2 = I_2 \times R \) - \( V_2 = 0.4 \, \text{A} \times 30 \, \Omega \) - \( V_2 = 12 \, \text{V} \).

3. Voltage on the Circuit Segment: - \( V_{\text{segment}} = I_{\text{total}} \times R_{\text{segment}} \) - \( V_{\text{segment}} = 0.9 \, \text{A} \times 30 \, \Omega \) - \( V_{\text{segment}} = 27 \, \text{V} \).

4. Resistance of Each Conductor: - \( R_1 = \frac{V_1}{I_1} \) - \( R_1 = \frac{15 \, \text{V}}{0.5 \, \text{A}} \) - \( R_1 = 30 \, \Omega \). - \( R_2 = \frac{V_2}{I_2} \) - \( R_2 = \frac{12 \, \text{V}}{0.4 \, \text{A}} \) - \( R_2 = 30 \, \Omega \).

Therefore, the current in the second conductor is 0.4 A, the voltage on the first conductor is 15 V, the voltage on the second conductor is 12 V, the voltage on the circuit segment is 27 V, and the resistance of each conductor is 30 Ohms.