Question

Даю 39 балов помогите !!! проводник с током длиной 15 см расположеный перпендиеулярно магнитному полю с индукцией 30 мтл, передвигается на 5 см под действием сил магнитного поля.в проводнике течёт ток с силой 30А. найти работу поля по перемещению проводника и с лу действующую на проводник​

Answer 1

Ответ:

13.30

Так как 30А-16МТЛ + сопротивление

Answer 2

Calculation of Work Done by the Magnetic Field on the Conductor

To calculate the work done by the magnetic field on the conductor, we need to use the formula:

Work (W) = Force (F) x Distance (d) x Cosine of the angle between the force and displacement (θ)

In this case, the force experienced by the conductor due to the magnetic field is given by:

F = I x L x B

Where: - I is the current flowing through the conductor (30 A) - L is the length of the conductor (15 cm = 0.15 m) - B is the magnetic field induction (30 mT = 0.03 T)

The distance traveled by the conductor is 5 cm = 0.05 m.

Now, let's calculate the work done by the magnetic field on the conductor:

W = F x d x cos(θ)

Since the conductor is moving perpendicular to the magnetic field, the angle between the force and displacement is 90 degrees, and the cosine of 90 degrees is 0.

Therefore, the work done by the magnetic field on the conductor is:

W = F x d x cos(90) = 0

The work done by the magnetic field on the conductor is zero because the force and displacement are perpendicular to each other.

Calculation of the Force Acting on the Conductor

To calculate the force acting on the conductor due to the magnetic field, we can use the formula:

F = I x L x B

Where: - I is the current flowing through the conductor (30 A) - L is the length of the conductor (15 cm = 0.15 m) - B is the magnetic field induction (30 mT = 0.03 T)

Now, let's calculate the force acting on the conductor:

F = 30 A x 0.15 m x 0.03 T = 0.135 N

Therefore, the force acting on the conductor due to the magnetic field is 0.135 N.