Question

Задача 1.Дві лампи розжарення розраховані на однсакову налругу 220 В, але мають різні потужності- 30 та 75 Вт. У скільки разів більше виділяється кількості теплоти в другій лампі, в порівнянні з першою, за однакові проміжки часу?Залежність опору спіралі від температури не враховуємо.

Answer 1

Ответ:

Объяснение:

U  = 220 В

P1 =  30Bт

P2 = 75 Вт

t = t1 = t2

Q2/ Q1 = ?

Q2 = P2*t

Q1 = P1*t

Q2/Q1 =  P2*t / (P1*t) = P2 / P1 = 75 / 30 = 2.5 раза

Answer 2

Problem Analysis

To solve this problem, we need to compare the amount of heat generated by two light bulbs with different power ratings when connected to the same voltage source.

Calculation

The amount of heat generated by a light bulb can be calculated using the formula: heat = power * time.

For the first bulb with a power of 30 W, the heat generated in a given time will be 30 * t.

For the second bulb with a power of 75 W, the heat generated in the same time will be 75 * t.

To find out how many times more heat is generated by the second bulb compared to the first, we can use the ratio of the heat generated by the second bulb to the heat generated by the first bulb: ratio = (75 * t) / (30 * t).

Solution

Simplifying the ratio, we get: ratio = 75 / 30.

So, the second bulb generates 2.5 times more heat than the first bulb for the same amount of time.

Therefore, the amount of heat generated by the second bulb is 2.5 times more than that generated by the first bulb for the same time period.

Final Answer

The second bulb generates 2.5 times more heat than the first bulb for the same amount of time.