
Задача по физике Плоскодонная баржа получила пробоину в дне площадью 160 см2 Рассчитай, с какой
силой нужно давить на пластырь, которым закрывают отверстие, чтобы сдержать напор воды на глубине 1,6 м. (Плотность воды р = 1000кг/м = 9,8Н/кг). Ответ (округли до десятых): сила, с которой нужно давить на пластырь, равна

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Ответ:
Объяснение:........




To calculate the force required to hold back the water pressure at a depth of 1.6 m in a flat-bottomed barge with a hole of 160 cm², we can use the formula for pressure:
Pressure = Force / Area
Given: - Area of the hole (A) = 160 cm² = 0.016 m² - Depth of the water (h) = 1.6 m - Density of water (ρ) = 1000 kg/m³ - Acceleration due to gravity (g) = 9.8 m/s²
We can calculate the force required to hold back the water pressure using the formula:
Force = Pressure × Area
To find the pressure, we can use the formula:
Pressure = Density × Gravity × Depth
Let's calculate the force required:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Let's calculate the force using the given values:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the values and calculate the force:
Calculation:
1. Convert the area of the hole to square meters: - Area (A) = 160 cm² = 0.016 m²2. Calculate the pressure at a depth of 1.6 m: - Pressure (P) = Density (ρ) × Gravity (g) × Depth (h) - P = 1000 kg/m³ × 9.8 m/s² × 1.6 m
3. Calculate the force required to hold back the water pressure: - Force (F) = Pressure (P) × Area (A) - F = P × A
Now, let's plug in the


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