Question

Плоскодонная баржа получила пробоину в дне площадью 190 см2 Определи, с какой силой нужно давить на пластырь, которым закрывают отверстие, чтобы сдержать напор воды на глубине 1,9 м. (Плотность воды р = g = 9,8H/кг). 1000кг/м3, Ответ (округли до десятых): сила, с которой нужно давить на пластырь, равна Н.​

Answer 1

Ответ: 353,8Н

Объяснение:

Дано:

S=190cм²=0,019м²

h=1,9м

g=9,8Н/кг

ρ=1000кг/м³

-------------------

F-?

F=рS=ρghS=1000*9,8*1,9*0,019=353,78Н=353,8Н

Answer 2

Calculating the Force Needed to Hold Back Water Pressure

To calculate the force needed to hold back the water pressure, we can use the formula:

F = P * A

Where: - F is the force needed - P is the pressure at the depth - A is the area of the hole

First, let's calculate the pressure at the given depth.

Calculating Pressure at Depth

The pressure at a given depth in a fluid can be calculated using the formula:

P = ρgh

Where: - P is the pressure - ρ is the density of the fluid - g is the acceleration due to gravity - h is the depth

Given: - Density of water, ρ = 1000 kg/m^3 - Acceleration due to gravity, g = 9.8 m/s^2 - Depth, h = 1.9 m

Plugging in the values: P = 1000 * 9.8 * 1.9

Calculating the Force

Now that we have the pressure, we can calculate the force needed to hold back the water pressure using the formula F = P * A.

Given: - Area of the hole, A = 190 cm^2 = 0.019 m^2 (converted from cm^2 to m^2)

Plugging in the values: F = 1000 * 9.8 * 1.9 * 0.019

Result

Calculating the above expression gives us the force needed to hold back the water pressure. Let's calculate the result.

F ≈ 353.2 N

So, the force needed to hold back the water pressure at a depth of 1.9 m, with a hole area of 190 cm^2, is approximately 353.2 N.