Question

При температуре 27°С давление газа в закрытом сосдуе было 75кПА. Каким будет давление при температуре -27'с?

Answer 1

Ответ:61,5 кПа

Объяснение:

Закон Шарля V=const, p1/T1=p2/T2,  p2=p1*T2/T1,

p2=75000Па*246К / 300К=61500 Па=61,5 кПа

Answer 2

Gas Pressure Calculation

To calculate the pressure of a gas at a different temperature, we can use the combined gas law, which states that the ratio of the pressure and temperature of a gas is constant if the volume and amount of gas are held constant.

The combined gas law formula is:

P1/T1 = P2/T2

Where: - P1 = initial pressure - T1 = initial temperature - P2 = final pressure (what we want to find) - T2 = final temperature

Calculation

Given: - Initial temperature (T1) = 27°C = 300K (approximately, using the conversion formula: K = °C + 273.15) - Initial pressure (P1) = 75 kPa - Final temperature (T2) = -27°C = 246K (approximately)

Using the combined gas law formula, we can solve for P2:

P1/T1 = P2/T2

75 kPa / 300K = P2 / 246K

Now, solving for P2:

P2 = (75 kPa * 246K) / 300K

P2 ≈ 61.5 kPa

So, the pressure of the gas at a temperature of -27°C would be approximately 61.5 kPa.