
Угол падения луча света на границу раздела воздух-жидкость равен 60°. Найдите синус угла
преломления, если скорость света в жидкости равна с (скорость света в воздухе равна с).

Ответы на вопрос

Ответ:
Объяснение:
где a - угол падения y-угол преломления v1-скорость в воздухе v2-скорость в жидкости
корень2/3 c
решаем и получаем ответ



Calculating the Refracted Angle
When a light ray passes from air into a liquid, the angle of incidence is given as 60°. We are asked to find the sine of the refracted angle when the speed of light in the liquid is equal to c (the speed of light in air).
To calculate the sine of the refracted angle, we can use the formula for the relationship between the angles of incidence and refraction and the speeds of light in the two media:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
Where: - n₁ and n₂ are the refractive indices of the initial and final media, respectively. - θ₁ is the angle of incidence. - θ₂ is the angle of refraction.
In this case, since the speed of light in the liquid is equal to the speed of light in air, the refractive indices of the two media are also equal.
Applying the Formula
Given that the speed of light in the liquid is equal to the speed of light in air, we can use the fact that the refractive index of a medium is inversely proportional to the speed of light in that medium. Therefore, if the speeds are equal, the refractive indices are also equal.
This means that n₁ = n₂.
Substituting this into the formula, we get:
sin(θ₁) = sin(θ₂)
This implies that the sine of the angle of incidence is equal to the sine of the angle of refraction.
Calculating the Sine of the Refracted Angle
Given that the sine of the angle of incidence is equal to the sine of the angle of refraction, we can directly calculate the sine of the refracted angle using the value of the angle of incidence.
The sine of the angle of refraction is therefore sin(60°).
Final Answer
The sine of the refracted angle, when the speed of light in the liquid is equal to the speed of light in air, is sin(60°).


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