Question

В калориметре находится 0,5 кг воды при температуре 10°С. В воду добавлен 1 кг льда при температуре 30°С. Если не учитывать теплоту калориметра, то какова его температура?​

Answer 1

Ответ:

Приближенно оценим, успеет ли вся вода превратиться в лёд. QB Q1+Q2 = cm(tB-t3)+^m = = 4200*0,5*(10-0)+340000*0,5 = 21000+170000= 191000 Дж. Qл = cm(tн-t3) = 2100*1*30=63000 Дж. Оценим, успеет ли весь лёд привротится в воду Qл1 = : cm(tr-t3)+^m = 2100*1*30+340000*1=403000Дж, QB2 = cm(tB-t3) =4200*0,5*10=210000 Дж. Значит, в калориметре окажется смесь воды и льда, с итоговой температурой о градусов.

Объяснение:

Удачи надеюсь помог

Answer 2

Calculation of Final Temperature

To calculate the final temperature of the system, we can use the principle of conservation of energy. The heat lost by the hot object (ice) is equal to the heat gained by the cold object (water). In this case, the hot object is the ice with a mass of 1 kg and an initial temperature of 30°C, and the cold object is the water with a mass of 0.5 kg and an initial temperature of 10°C.

Let's denote the final temperature of the system as T.

The heat lost by the ice can be calculated using the formula:

Q_lost = m_ice * c_ice * (T - T_ice_initial)

where: - m_ice is the mass of the ice (1 kg), - c_ice is the specific heat capacity of ice (which is approximately 2.09 kJ/kg°C), - T is the final temperature of the system, - T_ice_initial is the initial temperature of the ice (30°C).

The heat gained by the water can be calculated using the formula:

Q_gained = m_water * c_water * (T - T_water_initial)

where: - m_water is the mass of the water (0.5 kg), - c_water is the specific heat capacity of water (which is approximately 4.18 kJ/kg°C), - T is the final temperature of the system, - T_water_initial is the initial temperature of the water (10°C).

According to the principle of conservation of energy, the heat lost by the ice is equal to the heat gained by the water:

Q_lost = Q_gained

Substituting the formulas for Q_lost and Q_gained, we get:

m_ice * c_ice * (T - T_ice_initial) = m_water * c_water * (T - T_water_initial)

Now we can solve this equation to find the final temperature T.

Let's calculate it step by step.

1. Multiply the mass of the ice by its specific heat capacity and subtract the product of the initial temperature of the ice and the specific heat capacity of the ice:

1 kg * 2.09 kJ/kg°C * (T - 30°C)

2. Multiply the mass of the water by its specific heat capacity and subtract the product of the initial temperature of the water and the specific heat capacity of the water:

0.5 kg * 4.18 kJ/kg°C * (T - 10°C)

3. Set the two expressions equal to each other and solve for T:

1 kg * 2.09 kJ/kg°C * (T - 30°C) = 0.5 kg * 4.18 kJ/kg°C * (T - 10°C)

Let's solve this equation to find the final temperature T.