Question

Маятник 35 секунд совершил 80 колебаний Найти период и чистоту колебаний

Answer 1

Объяснение:

Дано

t=35c

n=80

Найти

T=?

v=?

Решение

T=t÷n

T=35÷80=0,4375 c ≈0,4 c

v=n÷t

v=80÷35=2,28571 c`¹ ≈ 2,3 Гц

Ответ: ≈0,4с; ≈2,3 Гц

Answer 2

Calculation of Period and Frequency of Oscillations

To find the period and frequency of oscillations, we need to use the given information that the pendulum completed 80 oscillations in 35 seconds.

The period of an oscillation is the time taken for one complete cycle of motion. It can be calculated by dividing the total time taken by the number of oscillations. In this case, the period can be calculated as:

Period = Total time / Number of oscillations

Substituting the given values:

Period = 35 seconds / 80 oscillations

To find the frequency of oscillations, we can use the formula:

Frequency = 1 / Period

Now let's calculate the period and frequency.

Period: Using the given values, we can calculate the period as follows:

Period = 35 seconds / 80 oscillations = 0.4375 seconds

Frequency: Using the calculated period, we can find the frequency as follows:

Frequency = 1 / Period = 1 / 0.4375 seconds = 2.2857 Hz

Therefore, the period of oscillation is approximately 0.4375 seconds, and the frequency of oscillation is approximately 2.2857 Hz.

Please note that the calculations are based on the given information and may be subject to rounding errors.