Question

пластмасовый шарик массой 258г подвесили к пружине динамометра. она удлинилась на 8мм. найдите жёсткость пружины динамометра. ускорение свободного падения тела 9,8г/м. ответ округлите до целого

Answer 1

Ответ:

Жесткость пружины k=316 Н/м

Объяснение:

Дано:

m = 258 г = 0,258 кг

Δx = 8 мм = 0,008 м

_________________

k = ?

По закону Гука:

F = k·Δx

Жесткость пружины:

k = F / Δx = m·g / Δx

k = 0,258·9,8 / 0,008 ≈ 316 Н/м

Answer 2

Ответ:

Жестокость пружины = k 316 Н/m

Answer 3

Calculation of the Spring Constant

To find the spring constant of the dynamometer spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force applied to the spring (in Newtons) - k is the spring constant (in Newtons per meter) - x is the displacement of the spring (in meters)

In this case, the mass of the plastic ball is given as 258 grams, which is equivalent to 0.258 kilograms. The displacement of the spring is given as 8 mm, which is equivalent to 0.008 meters. The acceleration due to gravity is given as 9.8 m/s^2.

To find the spring constant, we need to calculate the force applied to the spring. The force can be calculated using the formula:

F = m * g

Where: - m is the mass of the ball (in kilograms) - g is the acceleration due to gravity (in meters per second squared)

Let's calculate the force applied to the spring:

F = 0.258 kg * 9.8 m/s^2

Using the given values, we find:

F = 2.5264 N

Now, we can use Hooke's Law to find the spring constant:

F = k * x

Substituting the values we have:

2.5264 N = k * 0.008 m

Solving for k:

k = 2.5264 N / 0.008 m

Calculating the value:

k = 315.8 N/m

Therefore, the spring constant of the dynamometer spring is approximately 316 N/m.

Please note that the answer has been rounded to the nearest whole number, as requested.