Question

Какое количество теплоты необходимо передать воде массой 6 кг, чтобы ее нагреть от 30 °С до кипения?

Answer 1

Ответ:

Q=1,7МДж

Объяснение:

Answer 2

Calculating Heat Required to Raise the Temperature of Water

To calculate the heat required to raise the temperature of water from 30°C to its boiling point, we can use the formula:

Q = mcΔT

Where: - Q = heat energy (in joules) - m = mass of the water (in kg) - c = specific heat capacity of water (in J/kg°C) - ΔT = change in temperature (in °C)

Given: - m = 6 kg - Initial temperature = 30°C - Final temperature (boiling point) = 100°C

We can calculate the heat required using the specific heat capacity of water, which is approximately 4186 J/kg°C.

Using the formula, we get:

Q = 6 kg * 4186 J/kg°C * (100°C - 30°C)

Q = 6 kg * 4186 J/kg°C * 70°C

Q = 1761240 J

So, the amount of heat required to raise the temperature of 6 kg of water from 30°C to its boiling point is approximately 1,761,240 joules.