Question

Стальной баллон наполнен водородом при температуре 12 град. С. Давление водорода 15МПа. Найти плотность водорода?

Answer 1

P*M=p*R*T
p=P*M/R*T=15*10^6*28*10^-3/8,31*285=1773 кг/м3
Объяснение:

Answer 2

Calculating the Density of Hydrogen Gas

To calculate the density of hydrogen gas, we can use the ideal gas law equation, which is given by:

PV = nRT

Where: - P = pressure of the gas (in Pascals) - V = volume of the gas (in cubic meters) - n = number of moles of the gas - R = ideal gas constant (8.314 J/(mol·K)) - T = temperature of the gas (in Kelvin)

We can rearrange the equation to solve for the density (ρ) of the gas:

ρ = (P * M) / (R * T)

Where: - ρ = density of the gas (in kg/m³) - P = pressure of the gas (in Pascals) - M = molar mass of the gas (in kg/mol) - R = ideal gas constant (8.314 J/(mol·K)) - T = temperature of the gas (in Kelvin)

Given Values

- Temperature (T) = 12°C = 285.15 K (adding 273.15 to convert to Kelvin) - Pressure (P) = 15 MPa = 15,000,000 Pa - Molar mass of hydrogen (M) = 0.002 kg/mol (from periodic table)

Calculation

Using the given values and the formula for density, we can calculate the density of hydrogen gas:

ρ = (P * M) / (R * T)

ρ = (15,000,000 * 0.002) / (8.314 * 285.15)

ρ ≈ 0.111 kg/m³

So, the density of hydrogen gas at a temperature of 12°C and a pressure of 15 MPa is approximately 0.111 kg/m³.