Question

Два сообщающихся сосуда с различными поперечными сечениями наполнены водой. Площадь поперечного сечения у узкого сосуда в 10 раз меньше, чем у широкого. На узкий поршень поставили гирю весом 2Н. Найди, какой груз надо положить на широкий поршень, чтобы оба груза находились в равновесии. Ответ: на широкий поршень надо положить груз весом кн.​

Answer 1

Ответ: 20Н

Объяснение:

Дано:

S1=S

S2=10S

F1=2Н

------------

F2-?

F1/S1=F2/S2

F2=F1*S2/S1=2*10S/S=20Н

Answer 2

Problem Analysis

We have two communicating vessels filled with water. The narrow vessel has a cross-sectional area that is 10 times smaller than the wide vessel. A weight of 2N is placed on the narrow piston. We need to find the weight that should be placed on the wide piston to achieve equilibrium.

Solution

To solve this problem, we can use Pascal's law, which states that the pressure applied to a fluid in a closed container is transmitted equally in all directions.

Let's assume that the narrow vessel has a cross-sectional area of A1, and the wide vessel has a cross-sectional area of A2. We are given that A1 is 10 times smaller than A2.

According to Pascal's law, the pressure applied to the narrow piston is transmitted equally to the wide piston. Therefore, the pressure on both pistons is the same.

The pressure on a piston is given by the formula:

Pressure = Force / Area

Let's denote the weight placed on the narrow piston as W1 and the weight placed on the wide piston as W2.

Since the pressure is the same on both pistons, we can set up the following equation:

W1 / A1 = W2 / A2

We are given that W1 = 2N and A1 = A2 / 10.

Substituting these values into the equation, we get:

2N / (A2 / 10) = W2 / A2

Simplifying the equation, we get:

W2 = (2N * A2) / (A2 / 10)

Simplifying further, we get:

W2 = 20N

Therefore, the weight that needs to be placed on the wide piston to achieve equilibrium is 20N.

Answer

To achieve equilibrium, a weight of 20N should be placed on the wide piston.

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