Question

частота свободных колебаний колебательного контура , содержащего катушку индуктивности L-0.08Гн, равна v=600Гц. Какова ёмкость конденсатора этого контура?​

Answer 1

Ответ:

v= 1/ (2pi√(LC))

√C = 1/ (v2pi√L)

C = 1/ ((v2pi)^2L)=1/((800*2pi)^2*0.04)

С = 9.89465*10^-7 Ф =0.989465

Answer 2

Calculating Capacitance of the Oscillatory Circuit

The frequency of free oscillations in an oscillatory circuit containing an inductance coil L of 0.08 H is given as v = 600 Hz. We can calculate the capacitance of the capacitor in this circuit using the formula:

C = 1 / (4π²v²L)

Where: - C is the capacitance of the capacitor - v is the frequency of the oscillations - L is the inductance of the coil

Let's calculate the capacitance using the given values.

Calculating the Capacitance: Using the given values: - L = 0.08 H - v = 600 Hz

We can calculate the capacitance using the formula: C = 1 / (4π²v²L)

C = 1 / (4π² * (600 Hz)² * 0.08 H)

C ≈ 1 / (4 * 3.14² * 360000 Hz² * 0.08 H)

C ≈ 1 / (4 * 3.14² * 28800 Hz²)

C ≈ 1 / (4 * 28800 * 9.86)

C ≈ 1 / 113256

C ≈ 8.83 x 10^-6 F

So, the capacitance of the capacitor in this oscillatory circuit is approximately 8.83 x 10^-6 Farads.