Question

Прямолинейный проводник длиной 10 см расположен перпендику- лярно к вектору индукции B однородного магнитного поля. Какова сила Ампера, действующая на проводник, при силе тока в проводнике 200 мА и модуле индукции магнитного поля 0,5 Тл? Надо с Дано и Решением

Answer 1

Ответ:

0.01 H

Объяснение:

L=0.1 м    I=0.2 A    B=0.5 Тл    F=?

===

F=I*B*L=0.2*0.5*0.1=0.01 H

==========================

Answer 2

Given:

A straight conductor of length 10 cm is positioned perpendicular to the induction vector B of a homogeneous magnetic field. The current in the conductor is 200 mA, and the magnitude of the magnetic field induction is 0.5 T.

Formula for Ampère's Force:

The force experienced by a current-carrying conductor in a magnetic field is given by the formula: F = B * I * l

Where: - F is the force experienced by the conductor (in Newtons) - B is the magnitude of the magnetic field induction (in Tesla) - I is the current in the conductor (in Amperes) - l is the length of the conductor (in meters)

Solution:

Given: - Current, I = 200 mA = 0.2 A - Length of the conductor, l = 10 cm = 0.1 m - Magnitude of the magnetic field induction, B = 0.5 T

Using the formula F = B * I * l, we can calculate the force experienced by the conductor.

Calculation:

F = B * I * l F = 0.5 T * 0.2 A * 0.1 m F = 0.01 N

Answer:

The force (Ampère's force) acting on the conductor is 0.01 N.