Question

Найдите объём шарика из неизвестного металла, если в воздухе его вес составляет 560 Н, а будучи полностью погруженным в воду, он действует на пружину динамометра с силой 490 Н. Ответ дайте в кубических метрах СРОЧНО​

Answer 1

Ответ:

Объяснение:

Дано:

P₁ = 560 Н

P₂ = 490 Н

_________

V - ?

Выталкивающая сила:

Fₐ = P₁ - P₂ = 560 - 490 = 70 Н

Но:

Fₐ = ρ·g·V

Объем шарика:

V = Fₐ / (ρ·g)

V = 70 / (1000·10) = 0,007 м³

Answer 2

Finding the Volume of the Unknown Metal Sphere

To find the volume of the unknown metal sphere, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Given the information provided, we know that when the sphere is in the air, its weight is 560 N. When it is fully submerged in water, it exerts a force of 490 N on the spring of a dynamometer.

Using Archimedes' principle, we can set up the following equation:

Weight of the sphere in air = Weight of the sphere in water

The weight of the sphere in air is equal to its mass multiplied by the acceleration due to gravity (g), which is approximately 9.8 m/s^2. The weight of the sphere in water is equal to the buoyant force acting on it, which is equal to the weight of the water displaced by the sphere.

Let's denote the volume of the sphere as V and the density of the unknown metal as ρ.

The weight of the sphere in air can be calculated as: Weight in air = mass x g = ρ x V x g The weight of the sphere in water can be calculated as: Weight in water = buoyant force = weight of water displaced = ρ_water x V x g Since the sphere is fully submerged in water, the weight in water is equal to the force it exerts on the dynamometer, which is given as 490 N.

Setting up the equation: Weight in air = Weight in water ρ x V x g = ρ_water x V x g

The acceleration due to gravity (g) and the density of water (ρ_water) cancel out, leaving us with: ρ x V = 490

Now we can solve for the volume of the sphere (V): V = 490 / ρ

Unfortunately, the density of the unknown metal (ρ) is not provided in the question. Without this information, we cannot calculate the volume of the sphere.

Please provide the density of the unknown metal, and I will be able to calculate the volume for you.