Question

ФИЗИКА ЗА 30 БАЛОВ можно ли электрическим чайником мощностью 2,2 кВт, рассчитанным на работу от бытовой электросети, вскипятить 200мл воды, взятой при температуре 300К, подключив его к аккумуляторной батарее вашего телефона?

Answer 1

Відповідь:

нет и еще раз нет!

Пояснення:

Давайте размышлять так:  мощность 2200 вт, напряжение сети для такого прибора 220В   сила тока для того , что бы чайник работал нужна 2200/220=10 а  

аккум в телефоне(в очень хор.телефоне 2,5 а, а в основном до 2 а), если мы поключим аккум.телефона к такой нагрузке, он "сядет" за пару секунд, поэтому вы не только не вскипятите своих 200 мл воды, а потом и можете выкинуть свой аккум, а может и нет, как повезёт.

а теперь про уловку задачи в 300К     300 по Кельвину это температура по цельсию ≈26°  нам предлагают нагреть  до 100° практически  теплую воду.

короче-задача на внимание и на сообразительность.Вскипятить воду, то есть довести её до кипения, при таких условиях невозможно, мощность аккумулятора телефона на  подачу такой энергии недостаточно.

Answer 2

Can a 2.2 kW electric kettle, designed to work from a household electrical network, boil 200 ml of water taken at a temperature of 300 K by connecting it to your phone's battery?

To answer this question, we need to consider the power requirements of the electric kettle and the capacity of your phone's battery.

An electric kettle with a power rating of 2.2 kW (kilowatts) is designed to operate from a household electrical network, typically at a voltage of 220-240 volts. The power rating indicates the rate at which the kettle can convert electrical energy into heat energy.

To determine if the kettle can boil 200 ml of water taken at a temperature of 300 K (Kelvin), we need to calculate the amount of heat energy required to raise the temperature of the water from 300 K to its boiling point.

The specific heat capacity of water is approximately 4.18 J/g·K (joules per gram per Kelvin). To calculate the heat energy required, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat energy required (in joules) - m is the mass of the water (in grams) - c is the specific heat capacity of water (in J/g·K) - ΔT is the change in temperature (in Kelvin)

Given that we have 200 ml of water, we need to convert it to grams. The density of water is approximately 1 g/ml, so 200 ml of water is equivalent to 200 grams.

Now, let's calculate the heat energy required:

Q = 200 g * 4.18 J/g·K * (100 - 300) K

Simplifying the equation:

Q = 200 g * 4.18 J/g·K * (-200) K

Q = -167,200 J

From the calculation, we can see that the heat energy required to raise the temperature of 200 ml of water from 300 K to its boiling point is -167,200 J (negative value indicates heat loss).

Now, let's consider the capacity of your phone's battery. The capacity of a phone battery is typically measured in milliampere-hours (mAh) or watt-hours (Wh). To determine if your phone's battery can provide the required energy, we need to know its capacity in watt-hours.

Unfortunately, without specific information about your phone's battery capacity, it is difficult to determine if it can provide the necessary energy to boil the water. Phone batteries are generally not designed to power high-energy devices like electric kettles.

In conclusion, it is unlikely that you can use your phone's battery to power a 2.2 kW electric kettle and boil 200 ml of water taken at a temperature of 300 K. The power requirements of the kettle exceed the capacity of most phone batteries.