Question

З'єднали послідовно два провідники опором 6 Ом 1 12 Ом. Сила струму у першому провіднику 5А. Яка сила струму у другому провіднику?​

Answer 1

Ответ: 5А

Объяснение:

Дано:

R1=6 Ом

R2=12 Ом

I1=5A

соединены последовательно.

----------------------------

I2-?

При последовательном соединении сила тока во всех проводниках цепи одинакова.

I2=I1=5А

Answer 2

Calculation of Current in the Second Conductor

To calculate the current in the second conductor when two conductors with resistances of 6 ohms and 12 ohms are connected in series and a current of 5A flows through the first conductor, we can use the formula for calculating current in a series circuit.

According to Ohm's law, the current (I) flowing through a conductor can be calculated using the formula:

I = V / R

Where: - I = current in the conductor (in amperes, A) - V = voltage across the conductor (in volts, V) - R = resistance of the conductor (in ohms, Ω)

When conductors are connected in series, the same current flows through each conductor. Therefore, the current in the second conductor can be calculated using the total resistance of the circuit and the given current in the first conductor.

The total resistance (R_total) in a series circuit is the sum of the individual resistances: R_total = R1 + R2

Given: - Resistance of the first conductor (R1) = 6 ohms - Resistance of the second conductor (R2) = 12 ohms - Current in the first conductor (I1) = 5A

Using the formula for total resistance, we can calculate the total resistance in the circuit: R_total = 6Ω + 12Ω = 18Ω

Now, we can use the total resistance and the current in the first conductor to calculate the current in the second conductor using the formula: I2 = V / R2

Since the voltage across both conductors is the same in a series circuit, we can use the total current and the resistance of the second conductor to calculate the current in the second conductor: I2 = I_total * (R_total / R2)

Substituting the given values: I2 = 5A * (18Ω / 12Ω) = 7.5A

Therefore, the current in the second conductor is 7.5A.