Question

Какую работу совершает электродвигатель мощностью 6,3 кВт за 1,5 минуты? ответ дать в кДж

Answer 1

Ответ:

На фото решеніе.

Объяснение:

Answer 2

Объяснение:

N=A:t => A=N*t

A=6300Вт*90с = 56700Дж = 567кДж

Answer 3

Calculating Work Done by a 6.3 kW Electric Motor in 1.5 Minutes

To calculate the work done by an electric motor with a power of 6.3 kW in 1.5 minutes, we can use the formula:

Work (in joules) = Power (in watts) × Time (in seconds)

First, we need to convert the power from kilowatts to watts: 6.3 kW = 6300 watts

Now, we can calculate the work done: Work = 6300 watts × (1.5 minutes × 60 seconds/minute) Work = 6300 watts × 90 seconds Work = 567000 joules

Therefore, the work done by the electric motor with a power of 6.3 kW in 1.5 minutes is 567000 joules.

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