Question

Какую работу совершает ток в лампе за 40 с при силе тока в 2,5 А? Напряжение на лампе равно 220 В Запиши ответ числом. Дж

Answer 1

Ответ:

A=U*I*t

A=220В*2,5А*40с=22000Дж

Объяснение:

Answer 2

Calculation of Work Done by the Current in the Lamp

To calculate the work done by the current in the lamp, we can use the formula:

Work (W) = Power (P) × Time (t)

The power (P) can be calculated using the formula:

Power (P) = Voltage (V) × Current (I)

Given: - Current (I) = 2.5 A - Voltage (V) = 220 V - Time (t) = 40 s

First, let's calculate the power (P) using the given current and voltage:

Power (P) = 220 V × 2.5 A

Using the above formula, we can calculate the power.

Now, we can calculate the work (W) using the power and time:

Work (W) = Power (P) × Time (t)

Let's calculate the work done by the current in the lamp.

Calculation:

Power (P) = 220 V × 2.5 A = 550 W

Work (W) = 550 W × 40 s = 22,000 J

Therefore, the work done by the current in the lamp in 40 seconds, with a current of 2.5 A and a voltage of 220 V, is 22,000 J.

Please note that the above calculation assumes that the power remains constant during the 40-second period.