Question

Якою повинна бути температура повітря, щоб при тиску 5×10 Пa його густина була нормальною? 100 баллов​

Answer 1

Ответ:

Объяснение:..........

Answer 2

Calculating Air Density at a Given Pressure

To calculate the air density at a given pressure, we can use the ideal gas law equation, which states that:

PV = nRT

Where: - P is the pressure in pascals (Pa) - V is the volume in cubic meters (m³) - n is the number of moles of gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature in kelvin (K)

We can rearrange the equation to solve for density (ρ), which is mass per unit volume:

ρ = n / V

Given the pressure (P) as 5×10^5 Pa, we need to determine the temperature (T) at which the air density would be considered "normal."

Determining Normal Air Density

The "normal" air density can be considered to be the density of air at standard conditions, which is defined as 101.325 kPa (or 101,325 Pa) and 273.15 K (0 degrees Celsius).

To find the temperature at which the air density would be normal at a pressure of 5×10^5 Pa, we can rearrange the ideal gas law equation to solve for temperature (T):

T = (P * V) / (n * R)

Given that the volume (V) and the number of moles of gas (n) are not provided, we can't calculate the exact temperature. However, we can use the ideal gas law to determine the relationship between pressure and temperature for a given volume and number of moles of gas.

Conclusion

To determine the temperature at which the air density would be normal at a pressure of 5×10^5 Pa, we would need additional information such as the volume and the number of moles of gas. Once this information is provided, we can calculate the temperature using the ideal gas law equation.