Question

Помогите пожалуйста В воздухе чугунная деталь растянула пружину динамометра с силой 8,9 H, а в воде — с силой 4,8 Н. Какая выталкивающая сила действует на деталь в воде? OM Выталкивающая сила равна Н.

Answer 1

Ответ:

Объяснение:

Дано:

P₀ = 8,9 Н - вес детали в воздухе

P  = 4,8 Н - вес детали в воде

________________

Fₐ - ?

Выталкивающая сила (сила Архимеда):

Fₐ = P₀ - P

Fₐ = 8,9 - 4,8 = 4,1 H

Answer 2

Calculation of Buoyant Force

To calculate the buoyant force acting on the iron detail in water, we can use Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

The buoyant force can be calculated using the formula: Buoyant force = Weight of the fluid displaced

Calculation in Water

Given: - Force in air = 8.9 N - Force in water = 4.8 N

To find the buoyant force in water, we can use the difference between the force in air and the force in water: Buoyant force in water = Force in air - Force in water

Substituting the given values: Buoyant force in water = 8.9 N - 4.8 N

Calculation

Let's calculate the buoyant force in water: Buoyant force in water = 4.1 N

Therefore, the buoyant force acting on the iron detail in water is 4.1 N.