Вопрос задан 15.06.2023 в 02:53. Предмет Физика. Спрашивает Калижан Анель.

Розв'язування задач 2. В освітлювальну мережу кімнати ввімкнені паралельно дві електричні лампи,

опір яких 200 і 300 Ом. Напруга в мережі 220 в. Визначте силу струму в кожній лампі, силу струму в підвідних проводах, загальний опір обох ламп. Если можно с дано .​
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Отвечает Миронов Максим.

Ответ: 1,1А; 0,7А4 1,8А; 122,2 Ом

Объяснение:

Дано:

R1=200 Ом

R2=300 Ом

U=220В

-------------------

I1-?; I2-?; I-?;

R-?

I1=U/R1=220/200=1,1А

I2=U/R2=220/300=0,7А

I=I1+I2=1,1+0,7=1,8А

R=U/I=220/1,8=122,2 Ом

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Problem Analysis

To solve this problem, we need to determine the current flowing through each lamp, the current flowing through the connecting wires, and the total resistance of both lamps.

Given Information

- Resistance of the first lamp: 200 Ω - Resistance of the second lamp: 300 Ω - Voltage in the circuit: 220 V

Calculating Current through Each Lamp

To calculate the current flowing through each lamp, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). Mathematically, it can be represented as:

I = V / R

For the first lamp: - Resistance (R1) = 200 Ω - Voltage (V) = 220 V

Substituting these values into the formula, we can calculate the current (I1) flowing through the first lamp:

I1 = 220 V / 200 Ω

For the second lamp: - Resistance (R2) = 300 Ω - Voltage (V) = 220 V

Substituting these values into the formula, we can calculate the current (I2) flowing through the second lamp:

I2 = 220 V / 300 Ω

Calculating Current through Connecting Wires

To calculate the current flowing through the connecting wires, we can use Kirchhoff's Current Law, which states that the sum of currents entering a junction in a circuit is equal to the sum of currents leaving that junction. Since the lamps are connected in parallel, the current flowing through the connecting wires will be the sum of the currents through each lamp.

Total Current (Itotal) = I1 + I2

Calculating Total Resistance

To calculate the total resistance of both lamps, we can use the formula for resistors connected in parallel. The formula is:

1 / Rtotal = 1 / R1 + 1 / R2

Substituting the given resistance values, we can calculate the total resistance (Rtotal).

Solution

Let's calculate the values step by step:

1. Calculate the current through the first lamp (I1):

I1 = 220 V / 200 Ω

2. Calculate the current through the second lamp (I2):

I2 = 220 V / 300 Ω

3. Calculate the total current through the connecting wires (Itotal):

Itotal = I1 + I2

4. Calculate the total resistance (Rtotal):

1 / Rtotal = 1 / R1 + 1 / R2

Now, let's substitute the given values and calculate the results.

Calculation

1. Current through the first lamp (I1):

I1 = 220 V / 200 Ω

2. Current through the second lamp (I2):

I2 = 220 V / 300 Ω

3. Total current through the connecting wires (Itotal):

Itotal = I1 + I2

4. Total resistance (Rtotal):

1 / Rtotal = 1 / R1 + 1 / R2

Results

After performing the calculations, we find the following results:

- Current through the first lamp (I1): 1.1 A - Current through the second lamp (I2): 0.733 A - Total current through the connecting wires (Itotal): 1.833 A - Total resistance (Rtotal): 120 Ω

Please note that these results are based on the given information and the calculations performed.

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