Question

Пружина жесткостью 400 Н/м растянулась на 10 см. Определить максимальную потенциальную энергию пружины. Пружина находится в горизонтальном положении. A spring with a stiffness of 400 N/m was stretched by 10 cm. Determine the maximum potential energy of the spring. The spring is in a horizontal position.​

Answer 1

Ответ:

к=400н/м

х=10см=0,1м

Eп=кх²/2

Еп=400Н/м*0,01м²/2=2Дж

Answer 2

To determine the maximum potential energy of the spring, we can use the formula for potential energy stored in a spring:

E = (1/2)kx^2

where E is the potential energy, k is the stiffness of the spring, and x is the displacement from its equilibrium position.

In this case, the stiffness of the spring is given as 400 N/m and the displacement is 10 cm, which is equivalent to 0.1 meters. Substituting these values into the formula, we can calculate the maximum potential energy:

E = (1/2)(400 N/m)(0.1 m)^2 = (1/2)(400 N/m)(0.01 m^2) = 2 N⋅m

Therefore, the maximum potential energy of the spring is 2 N⋅m.