Question

R1=10кОм R2=10ом R3=15Ом Vобщ=110В Найти i1,i2,i3,iобщ V1,V2,V

Answer 1

i1=V/R1=110/10000=11mA

i2=V/R2=11A

i3=V/R3=7,3A

iо=V/Rо=11mA

V1=i*r=110В

V2=110В

V3=110B

Answer 2

To solve this circuit, we can use Ohm's Law and Kirchhoff's Laws.

First, let's calculate the total resistance of the circuit:

Rобщ = R1 + R2||R3 = R1 + (R2 * R3)/(R2 + R3) = 10,000 + (10 * 15)/(10 + 15) = 11,000 Ω

where R2||R3 is the parallel combination of R2 and R3.

Now, we can use Ohm's Law to find the current through each resistor:

i1 = (Vобщ - V1) / R1 i2 = V1 / R2 i3 = V2 / R3 iобщ = (Vобщ - V2) / Rобщ

where V1 and V2 are the voltages across R2 and R3, respectively.

Next, we can apply Kirchhoff's Voltage Law (KVL) to the outer loop of the circuit to find the voltage drop across R1 and R2+R3:

Vобщ = V1 + V2 + i1R1 + i2(R2+R3)

Finally, we can solve the equations simultaneously to find all the unknowns:

i1 = (Vобщ - V1) / R1 i2 = V1 / R2 i3 = V2 / R3 iобщ = (Vобщ - V2) / Rобщ

Vобщ = V1 + V2 + i1R1 + i2(R2+R3)

Substituting the values, we get:

i1 = 1.0 mA i2 = 0.11 A i3 = 7.33 mA iобщ = 9.91 mA V1 = 1.1 V V2 = 1.65 V V = V1 + V2 = 2.75 V

Therefore, the current through each resistor is i1 = 1.0 mA, i2 = 0.11 A, and i3 = 7.33 mA. The total current through the circuit is iобщ = 9.91 mA. The voltage drop across R1 is V1 = 1.1 V, and the voltage drop across R2 and R3 is V2 = 1.65 V. The voltage across the voltage source is V = V1 + V2 = 2.75 V.