Question

V0=360км/ч a=9м/с^ t=10c V-? S-?

Answer 1

S=V0*t+at^2/2  S=100*10+9*100/2=1450m       V=V0+at  V=100+90=190m/c

Answer 2

Given the initial velocity (V0) of 360 km/h (converted to m/s, it is 100 m/s), an acceleration (a) of 9 m/s^2, and a time (t) of 10 seconds, we can calculate the final velocity (V) and the distance covered (S) using the equations of motion.

1. Final Velocity (V): The equation to calculate the final velocity is:

V = V0 + at

Plugging in the values:

V = 100 m/s + (9 m/s^2)(10 s) V = 100 m/s + 90 m/s V = 190 m/s

Therefore, the final velocity (V) is 190 m/s.

2. Distance Covered (S): The equation to calculate the distance covered is:

S = V0t + (1/2)at^2

Plugging in the values:

S = (100 m/s)(10 s) + (1/2)(9 m/s^2)(10 s)^2 S = 1000 m + (1/2)(9 m/s^2)(100 s^2) S = 1000 m + (1/2)(9)(10,000 s^2) S = 1000 m + 45,000 m S = 46,000 m

Therefore, the distance covered (S) is 46,000 meters or 46 kilometers.