Question

V=10л P=1,5мПа V'=40л P'=?

Answer 1

Ответ:

V = 10 л =10^-2 м3 = const

p1 = 10 атм = 10^6 Па

T1 = 27 С. +273 = 300 K

T2 = 17 С. +273 = 290 K

m = 10 г

M= 4 г/моль        гелий

R=8.31 Дж/кг*К

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p2   - ?

 

 

уравнение состояния идеального газа

p1V = m1/M *RT1

m1 = p1VM / RТ1 =10^6*10^-2*2 /8.31*300 = 16 г

m2=m1-10 г = 16 г - 10 г = 6г

 

состояние 1

p1V = m1/M *RT1 ;  p1 /m1T1 =  R /MV

состояние 2

p2V = m2/M *RT2 ;  p2 /m2T2 =  R /MV

приравняем левые части уравнений

p1 /m1T1 =p2 /m2T2

p2 = p1 *m2/m1 *T1/T2 =10^6 *6/16 *300/290 =387931 Па = 388 кПа

 

ОТВЕТ 387931 Па = 388 кПа

Объяснение:

Answer 2

To find the pressure (P') when the volume (V') is 40 liters, given that the initial volume (V) is 10 liters and the initial pressure (P) is 1.5 MPa, we can use Boyle's Law. Boyle's Law states that the pressure and volume of a gas are inversely proportional when temperature is held constant.

Mathematically, Boyle's Law can be expressed as:

P * V = P' * V'

where P is the initial pressure, V is the initial volume, P' is the final pressure, and V' is the final volume.

Plugging in the given values:

1.5 MPa * 10 L = P' * 40 L

Simplifying the equation:

15 MPa * L = 40 P' * L

Canceling out the common unit (L) on both sides:

15 MPa = 40 P'

Finally, we can solve for P':

P' = 15 MPa / 40 P' = 0.375 MPa

Therefore, when the volume is 40 liters, the pressure is 0.375 MPa.