Question

Решите плуиз х+1240-229=2012 1926-(х+325)=1361 1924-(х+328)=1485 (х+884)-32=1604 (Х=129)-425=1021 1921-(Х-26)=1667

Answer 1

1)x = 2012 - 1240 + 229 = 1001
2) 1926 - x - 328 = 1485 ; -x = 1485 - 1926 + 328 = -113; x = 113
3) 1924 - x - 328 = 1485 ; -x = 1485 - 1924 + 328 = -111; x = 111
4) x = 1604 - 884 + 32 = 752
5) x = 1021 + 425 - 129 = 1317
6) -x = 1667 - 1921 - 26 = -280; x = 280

Answer 2

1. 2012+229= 1240+х=2241=1240+х

х=2241-1240=1001

Answer 3

Solving the Equation

To solve the given equation, we'll start by simplifying and solving each equation step by step.

1. Simplify the Equations: - Equation 1: \(x + 1240 - 229 = 2012\) - Equation 2: \(1926 - (x + 325) = 1361\) - Equation 3: \(1924 - (x + 328) = 1485\) - Equation 4: \((x + 884) - 32 = 1604\) - Equation 5: \(x - 425 = 1021\) - Equation 6: \(1921 - (x - 26) = 1667\)

2. Solve Each Equation: - Equation 1: \(x = 1001\) - Equation 2: \(x = 540\) - Equation 3: \(x = 111\) - Equation 4: \(x = 752\) - Equation 5: \(x = 1446\) - Equation 6: \(x = 1980\)

Final Solution:

The solutions for the given equations are: - \(x = 1001\) for the first equation. - \(x = 540\) for the second equation. - \(x = 111\) for the third equation. - \(x = 752\) for the fourth equation. - \(x = 1446\) for the fifth equation. - \(x = 1980\) for the sixth equation.

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