Question

Помогите с уравнением.

Answer 1

$2^{x+3} - 3^{ x^{2} +2x-6} = 3^{ x^{2} +2x-5} - 2^{x} \\ 2^{x+3}+2^x=3^{ x^{2} +2x-5}+3^{ x^{2} +2x-6} \\ 2^x(2^3+1)=3^{ x^{2} +2x-5}(1+3^{-1}) \\ 9\cdot 2^x= \frac{4}{3}\cdot 3^{ x^{2} +2x-5} \\ 2^{x-2}=3^{x^2+2x-8} \\ 2^{x-2}=3^{(x+4)(x-2)} \\ 2^{x-2}=(3^{x+4})^{x-2} \\ 3^{x+4}=2 \\ log_33^{x+4}=log_32 \\ x+4=log_32 \\ x=log_32-4$

Answer 2

Solving an Equation

To help you with solving an equation, I'll need more specific information about the equation you want to solve. Could you please provide the equation you would like assistance with?