Question

На тарелке лежат 4 пирожка с капустой 7 пирожков с грибами. Взяли наугад 5 пирожков. Какое наибольшее число пирожков с капустой могло остаться на тарелке?

Answer 1

Тарелка 1; лежат= 4 с капустой + 7 с грибами= 11 пирожков всех;

берем 5 из всех 11;
11-5=6осталось разных;

но наугад могли взять 5 пирожков только с грибами 7-5=2 с грибами осталось и 4 с капустой
2+4=6 всех;

Ответ: наибольшее число 4 пирожка с капустой могло остаться.

Answer 2

Calculating the Maximum Number of Cabbage Pies

To calculate the maximum number of cabbage pies that could remain on the plate after taking 5 pies at random, we can consider the following approach:

1. Total Number of Cabbage Pies: 4 2. Total Number of Mushroom Pies: 7 3. Total Number of Pies Taken: 5

To maximize the number of cabbage pies remaining, we should assume that all the pies taken were mushroom pies. This would leave the maximum number of cabbage pies on the plate.

Calculation

If all 5 pies taken were mushroom pies, then the number of cabbage pies remaining would be: 4 (initial cabbage pies) - 0 (pies taken) = 4 cabbage pies remaining

Therefore, the maximum number of cabbage pies that could remain on the plate is 4. This assumes that all 5 pies taken were mushroom pies.

Conclusion

By assuming that all the pies taken were mushroom pies, we can maximize the number of cabbage pies remaining on the plate to 4.