Question

Из города А в город Б выехал велосипедист через 3 часа в том же направлении из города А выехал мотоциклист и прибыл в город Б одновременно с велосипедистом. Найдите скорость велосипедиста, если она меньше чем скорость мотоциклиста на 45км\ч а расстояние между городами 60км.

Answer 1

Пусть скорость велосипедиста х , скорость мотоциклиста х+45. 

60/х - 60/(х+45)=3

Решив это уравнение найдем скорость велосипедиста.

Answer 2

Problem Analysis

We are given the following information: - A cyclist left city A for city B. - After 3 hours, a motorcyclist left city A in the same direction. - The motorcyclist arrived in city B at the same time as the cyclist. - The distance between the two cities is 60 km. - The cyclist's speed is 45 km/h slower than the motorcyclist's speed.

We need to find the speed of the cyclist.

Solution

Let's assume the speed of the cyclist is x km/h. Since the motorcyclist's speed is 45 km/h faster, the speed of the motorcyclist is x + 45 km/h.

We can use the formula distance = speed × time to calculate the time taken by each traveler.

The cyclist traveled for 3 hours, so the distance covered by the cyclist is 3x km.

The motorcyclist traveled for an unknown time, so let's call it t hours. The distance covered by the motorcyclist is (x + 45)t km.

Since both travelers arrived at the same time in city B, the distances covered by both of them are equal. Therefore, we can set up the following equation:

3x = (x + 45)t

Now, we can solve this equation to find the value of x, which represents the speed of the cyclist.

Calculation

Let's solve the equation:

3x = (x + 45)t

We know that the distance between the two cities is 60 km, so we can substitute 60 for t:

3x = (x + 45) × 60

Simplifying the equation:

3x = 60x + 2700

60x - 3x = 2700

57x = 2700

x = 2700 / 57

x ≈ 47.37

Therefore, the speed of the cyclist is approximately 47.37 km/h.

Answer

The speed of the cyclist is approximately 47.37 km/h.